Try these four original exercises without hints. This is a study checkpoint, not an official competition score or a prediction of qualification. Allow roughly 40–60 minutes and write explanations. Use the solutions only after recording an attempt.

1. Algebra

For positive real a,b with a + b = 8, prove 1/a + 1/b ≥ 1/2. When does equality hold?

Hint

Write the sum as (a+b)/(ab).

Full solution

(a − b)² ≥ 0 implies 4ab ≤ (a + b)² = 64, so 0 < ab ≤ 16. Thus 1/a + 1/b = 8/(ab) ≥ 8/16 = 1/2. Equality requires a = b; the sum condition gives a = b = 4.

Check your reasoning: If you missed why dividing reverses the comparison of denominators, revisit positive reciprocals and the algebra lesson.

2. Number theory

Show that 5 cannot divide n² + 2 for any integer n.

Hint

List the possible square remainders modulo 5.

Full solution

An integer is congruent to 0,1,2,3 or 4 modulo 5. Squaring gives remainders 0,1,4,4,1. Adding 2 gives 2,3 or 1 modulo 5, never 0. Therefore 5 does not divide n² + 2.

Check your reasoning: List all remainder classes. Checking only a few ordinary integers does not cover all integers.

3. Geometry

In triangle ABC, D lies on AB, E lies on AC, DE ∥ BC and AD:AB = 1:3. What fraction of the area of ABC lies in quadrilateral DBCE?

Similar triangles ADE and ABCD lies on AB, E lies on AC, and DE is parallel to BC. AD:AB = 1:3.ABCDE
D lies on AB, E lies on AC, and DE is parallel to BC. AD:AB = 1:3.

Hint

Subtract the small similar triangle from the whole triangle.

Full solution

Triangles ADE and ABC are similar by corresponding angles. Their linear ratio is 1/3, so area(ADE)/area(ABC) = 1/9. The remaining quadrilateral has area fraction 1 − 1/9 = 8/9. The diagram and theorem in the geometry practice section show the same configuration with a different ratio.

Check your reasoning: Using 1/3 as the area ratio confuses length with area. Draw the labelled configuration before solving.

4. Combinatorics

Choose seven distinct integers from 1 through 12. Prove that two selected integers sum to 13.

Hint

Build six disjoint boxes with the desired sum.

Full solution

Partition the numbers into {1,12}, {2,11}, {3,10}, {4,9}, {5,8}, {6,7}. Seven choices into six boxes force a box containing two choices. Its numbers sum to 13.

Check your reasoning: Your boxes must cover every possible selected number, and each complete box must have the required property.

Mark the reasoning, then choose a route

For each problem, give yourself 0 if you have no valid route, 1 if the central idea is right but the explanation has a gap, or 2 if the argument is complete. This rubric is only for planning your study.

Your workNext step
0–1 on a subjectReturn to that subject in the practice plan; rewrite the solution and solve a related problem.
Mostly correct ideas, incomplete proofsStudy proof-writing; check domains, cases and the reason for each implication.
Complete solutions in all four subjectsSelect an official first-stage national paper; compare its level and format before timing yourself.

Do not add the scores into an IMO-readiness claim. Four short questions cannot measure performance on a full national selection test.